BAR NUMBERS - 2

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      How would you remove the bar number in 5  1  3 ? The best way is to split the number into two

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          parts: 51/3. Since 5 1 = 49, the answer is 493. 

If a number has a bar number in it split the number after the bar.

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7 3 1 = 7 3/1 = 671,  

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  52 4 2 = 52 4 /2 = 5162, 

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3 2 15 = 3 2 /15 = 2815 since 3 2 = 28, 

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5 1 3 2 = 51/ 32 = 4928 since 51 = 49 and 3 2 = 28, 

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 3 1 3 2 3 3 = 31/ 32 / 33 = 292827. 

                                           ALL FROM 9 AND THE LAST FROM 10

So far we have only had a bar on a single figure. But we could have two or more bar numbers together.

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  7 14 = 686 the 7 reduces to 6 and the Sutra converts 14 to 86, ( 10 compliment of 4 is 6 and 9 compliment of 1 is 8)

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26 21 = 2579                     26 reduces to 25, ( 9 and 10 compliment)

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7 02 = 698                           the Sutra converts 02 to 98, 

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50 3 = 497                       50 is reduced to 49 (alternatively, write 50 3 as 5 03: see previous example),

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4 20 = 4 2 0 = 380. 

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4 23 1 = 3771.  

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Here we can split the number after the bar: 4 23/1. 4 23 changes to 377, and we just put the 1 on the end: 4 231 = 3771. 

Practice C Remove the bar numbers: 

     __               __              __                            _                        __                 __

a 612         b 7 33          c511                     d 9 04                e 72 41       f 333 22   

      __              __                 __                        ___                                  ___

g 6 214      h 5 3122      i 33 22 44             j 7  333               k 5104 l 44112