Division by 9
As you have seen before, the number 9 is special and there is a very easy way to divide by 9.
Find 23 ÷ 9.
9) 2 3
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2 r 5
The first figure of 23 is the answer: 2.
And adding the figures of 23 gives the remainder: 2 + 3 = 5.
So 23 ÷ 9 = 2 remainder 5.
9*2=18; 18+5=23
43 ÷ 9.
9) 43
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4\7
Quotient 4 R 7
Practice A Divide by 9:
a 9)5 1 b 9)3 4 c 9)17 d 9)4 4
e 9)6 0 f 9)7 1 g 9)2 6 h 9)4 6
Harder cases of dividing by 9
More difficult cases of Nikhilam division occur when the numbers in the summation become too large. sometimes require remainder to be redivided.
Example 2137÷9
9 )2 1 3 / 7
_________
2 3 6 / 13
__________
1/ 4 The remainder is larger than the divisor so 13 is divided by 9 Q=1; R=4
___________
237 / 4 the 1 is added to the quotient making 237 remainder 4
In the second instance you can treat a two digit number as if it were a single digit number.
Example 5673÷9
9) 5 6 7 /3 Bring the 5 down. 5+6=11 ; 11+7=18 ; 18+3=21
___________
5 11 18 / 21 Treat 11,18 as a single number. 21÷9= 2 R=3
_______________
6 3 0 / 3 18+2=20; 11+2=13; 5+1=6
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